Statistics on the Digital SAT
Measures of center: mean, median, mode
A measure of center summarizes a dataset with a single number. The SAT uses all three:
Mean (average): sum of values divided by count. Sensitive to outliers.
Median: the middle value when the data is sorted. (For an even count, the average of the two middle values.) Robust to outliers.
Mode: the value that appears most often. A dataset can have no mode, one mode, or multiple modes.
Outliers shift the mean but barely move the median. If one student in a class of 20 scores 1500 while everyone else scores around 1000, the mean rises noticeably but the median barely changes. The SAT tests this intuition.
Measures of spread: range and standard deviation
Spread tells you how clustered or scattered the data is around the center.
Range: the maximum value minus the minimum value. Cares only about the extremes.
Standard deviation: roughly the average distance from the mean. The SAT doesn't ask you to calculate it — it asks you to compare standard deviations between datasets.
Rule of thumb for standard deviation: data that clusters tightly around the mean has a small standard deviation. Data that's spread out has a large one. If two datasets have the same mean but one is more "packed" together, its standard deviation is smaller.
Weighted averages
A regular mean treats every value equally. A weighted average assigns each value a weight (importance) and computes:
weighted mean = Σ(value × weight) / Σ(weights)
Example. A class has 20 students who scored an average of 80, and 30 students who scored an average of 90. What is the overall class average?
Weighted: (80 × 20 + 90 × 30) / (20 + 30) = (1600 + 2700) / 50 = 86.
Not 85 (the simple average of 80 and 90). Weights matter.
What happens when you add or remove a value?
The SAT loves to ask "if you add value X, what happens to the mean / median / standard deviation?" Predict before you compute:
- Adding a value equal to the mean: mean stays the same. Median might shift slightly toward it. Standard deviation decreases (data is more clustered).
- Adding an outlier above the mean: mean increases. Median barely moves. Standard deviation increases.
- Removing the smallest value: mean increases. Median shifts up. Standard deviation usually decreases.
Practice prediction: before doing any calculation, ask "is this new value above or below the current mean?" That tells you which direction the mean shifts.
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Solving with Desmos
Desmos' statistics features make these problems much faster. Three techniques:
1. Use stats(L) for instant calculations
L = [12, 15, 18, 20, 22]. Then type mean(L), median(L), stdev(L). Desmos returns the values immediately.2. Build a table to organize data
sum(values · weights) / sum(weights).3. Verify standard deviation comparisons by graphing
For the full set of Desmos techniques across the entire test, see our Desmos & Test Tools guides.
Common mistakes
Computing mean when the question asks for median
Median is the middle value, not the average. Sort the data first, then pick the middle (or average the two middles if even count). The mean and median can be very different.
Forgetting to sort before finding the median
The data {7, 2, 9, 4, 5} has median 5 (sorted: 2, 4, 5, 7, 9). Picking 9 because it's in the middle of the unsorted list is the #1 median mistake.
Treating a weighted average as a simple average
If 20 students scored 80 and 30 scored 90, the class average isn't (80+90)/2 = 85. It's (20·80 + 30·90)/(20+30) = 86. The bigger group pulls the mean toward its value.
Computing standard deviation by hand
The SAT never asks for the actual SD value — only comparisons. If you're computing it, you're wasting time. Compare visually (clustering) instead.
Practice problems
8 problems adapted from College Board released questions and internal Prepiii sets. Click each one to reveal the solution.
1What is the median of the dataset 5, 12, 7, 8, 15, 4, 10?
- 7
- 8
- 10
- 12
Click to reveal solution →
What is the median of the dataset 5, 12, 7, 8, 15, 4, 10?
- 7
- 8
- 10
- 12
Click to reveal solution →
Answer: (B) 8
Sort: 4, 5, 7, 8, 10, 12, 15. There are 7 values; the middle one (4th) is 8.
2The mean of five numbers is 14. If a sixth number is added and the mean rises to 16, what is the sixth number?
- 18
- 22
- 26
- 30
Click to reveal solution →
The mean of five numbers is 14. If a sixth number is added and the mean rises to 16, what is the sixth number?
- 18
- 22
- 26
- 30
Click to reveal solution →
Answer: (C) 26
Sum of original 5: 5 × 14 = 70.
New sum after adding sixth: 6 × 16 = 96.
Sixth number: 96 - 70 = 26.
3In a class of 30 students, the average exam score was 78. After a new student scored 92 on the same exam joined the class, what is the new average (rounded to the nearest tenth)?
- 78.0
- 78.3
- 78.5
- 79.0
Click to reveal solution →
In a class of 30 students, the average exam score was 78. After a new student scored 92 on the same exam joined the class, what is the new average (rounded to the nearest tenth)?
- 78.0
- 78.3
- 78.5
- 79.0
Click to reveal solution →
Answer: (C) 78.5
Original sum: 30 × 78 = 2340.
New sum: 2340 + 92 = 2432. New count: 31.
New mean: 2432 / 31 ≈ 78.45 → rounds to 78.5.
4Two classes take the same test. Class A (with 20 students) has a mean of 75. Class B (with 30 students) has a mean of 85. What is the mean of the combined group?
- 79
- 80
- 81
- 82
Click to reveal solution →
Two classes take the same test. Class A (with 20 students) has a mean of 75. Class B (with 30 students) has a mean of 85. What is the mean of the combined group?
- 79
- 80
- 81
- 82
Click to reveal solution →
Answer: (C) 81
Total sum: 20 · 75 + 30 · 85 = 1500 + 2550 = 4050.
Total students: 50. Combined mean: 4050 / 50 = 81.
5The mode of the dataset 3, 5, 5, 7, 9, 9, 9, 12 is:
- 5
- 7
- 9
- 9.5
Click to reveal solution →
The mode of the dataset 3, 5, 5, 7, 9, 9, 9, 12 is:
- 5
- 7
- 9
- 9.5
Click to reveal solution →
Answer: (C) 9
The mode is the most frequent value. 9 appears three times; 5 appears twice; everything else appears once.
6Dataset X: 10, 10, 10, 10, 10. Dataset Y: 2, 6, 10, 14, 18. Both have mean 10. Which has the smaller standard deviation?
- Dataset X
- Dataset Y
- They are equal
- Cannot be determined
Click to reveal solution →
Dataset X: 10, 10, 10, 10, 10. Dataset Y: 2, 6, 10, 14, 18. Both have mean 10. Which has the smaller standard deviation?
- Dataset X
- Dataset Y
- They are equal
- Cannot be determined
Click to reveal solution →
Answer: (A) Dataset X
Dataset X has every value exactly at the mean — zero spread, so standard deviation = 0. Dataset Y is spread out, so its SD is positive. X has the smaller SD.
7A teacher records test scores: 72, 85, 90, 78, 65, 88, 95, 80. What is the range?
- 20
- 25
- 30
- 35
Click to reveal solution →
A teacher records test scores: 72, 85, 90, 78, 65, 88, 95, 80. What is the range?
- 20
- 25
- 30
- 35
Click to reveal solution →
Answer: (C) 30
Max = 95, Min = 65. Range = 95 - 65 = 30.
8The mean of four numbers is 10. If a fifth number, equal to 20, is added to the dataset, what happens to the median?
- It increases
- It decreases
- It stays the same
- Cannot be determined without the original values
Click to reveal solution →
The mean of four numbers is 10. If a fifth number, equal to 20, is added to the dataset, what happens to the median?
- It increases
- It decreases
- It stays the same
- Cannot be determined without the original values
Click to reveal solution →
Answer: (D) Cannot be determined without the original values
Without knowing the actual numbers (only their mean), we can't determine the median or how it changes. Mean alone doesn't pin down the data distribution.
Frequently asked questions
What's the difference between mean, median, and mode?
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How do I calculate standard deviation on the SAT?
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What's a weighted average?
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How does adding an outlier affect the mean vs median?
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What's the range in statistics?
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