Linear Inequalities on the Digital SAT
Solving inequalities (mostly) like equations
A linear inequality is a linear equation with <, >, ≤, or ≥ instead of =. You solve it almost exactly the same way: use inverse operations to isolate the variable.
Example. Solve 3x + 4 > 19.
Subtract 4: 3x > 15.
Divide by 3: x > 5. (Solution: every x greater than 5.)
The solution is not a single number — it's a range. x > 5 includes 5.0001, 6, 7, 100, etc.
The flip-sign rule (the one twist)
When you multiply or divide both sides by a negative number, you must flip the inequality sign.
Example. Solve -2x > 8.
-2, AND flip > to <: x < -4.Why? Multiplying by a negative reverses the order on the number line. 3 > 1, but -3 < -1. The inequality sign reflects the new ordering.
Important: you don't flip when adding or subtracting negatives, or when dividing by a positive — only when multiplying or dividing both sides by a negative number.
Compound inequalities
A compound inequality has the variable trapped between two bounds, like 5 < 2x + 1 < 11. To solve, perform the same operation on all three parts simultaneously.
Example. Solve 5 < 2x + 1 < 11.
Subtract 1 from all three: 4 < 2x < 10.
Divide by 2: 2 < x < 5.
Solution: any x strictly between 2 and 5.
Graphing and systems of inequalities
Inequalities in two variables (like y < 2x + 3) graph as a half-plane bounded by a line. Conventions:
- Solid line for
≤or≥(the line is included). - Dashed line for
<or>(the line is excluded). - Shade above the line if
y > ...ory ≥ .... - Shade below the line if
y < ...ory ≤ ....
For a system of inequalities, graph each one and the solution is the region where the shadings overlap. Test a point (like (0, 0)) to verify it satisfies both inequalities.
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Solving with Desmos
Desmos handles inequalities natively. Type them as written and Desmos shades the solution region. Three techniques:
1. Graph the inequality directly
y > 2x + 3 and Desmos shades the half-plane above the line, with a dashed boundary (since >, not ≥).2. System of inequalities — find the overlap
3. Check if a point is a solution
(3, 4). Desmos plots it. If it's inside the shaded region of an inequality, it's a solution.For the full set of Desmos techniques across the entire test, see our Desmos & Test Tools guides.
Common mistakes
Forgetting to flip the sign with a negative
When you divide -3x > 12 by -3, the inequality flips: x < -4. Most students remember this on the first try and forget it on the third. Build the habit.
Flipping when you shouldn't
You only flip when multiplying or dividing by a negative — NOT when adding or subtracting a negative. 5 - 3 > 2 - 3 stays 2 > -1.
Confusing < with ≤ on the boundary
x < 5 does NOT include 5. x ≤ 5 includes 5. The SAT loves to put 5 in the answer choices to test this.
Shading the wrong side of the line
For y > [line], shade ABOVE the line, not below. Quick check: pick a test point like (0, 0), plug into the inequality. If the test point satisfies it, shade that side.
Practice problems
8 problems adapted from College Board released questions and internal Prepiii sets. Click each one to reveal the solution.
1If 5x - 3 < 12, what is the largest integer value of x?
- 1
- 2
- 3
- 4
Click to reveal solution →
If 5x - 3 < 12, what is the largest integer value of x?
- 1
- 2
- 3
- 4
Click to reveal solution →
Answer: (B) 2
Add 3: 5x < 15. Divide by 5: x < 3.
Since x must be strictly less than 3, the largest integer is 2.
2Solve -3x + 7 ≥ 19.
- x ≤ -4
- x ≥ -4
- x ≤ 4
- x ≥ 4
Click to reveal solution →
Solve -3x + 7 ≥ 19.
- x ≤ -4
- x ≥ -4
- x ≤ 4
- x ≥ 4
Click to reveal solution →
Answer: (A) x ≤ -4
Subtract 7: -3x ≥ 12.
Divide by -3 AND flip the sign: x ≤ -4.
3Which value of x is NOT a solution to 2 < 3x - 1 ≤ 14?
- 1
- 2
- 4
- 5
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Which value of x is NOT a solution to 2 < 3x - 1 ≤ 14?
- 1
- 2
- 4
- 5
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Answer: (A) 1
Solve: add 1 to all parts: 3 < 3x ≤ 15. Divide by 3: 1 < x ≤ 5.
x = 1 is NOT included (strict inequality). The others are.
4Maria has at most $60 to spend on apples and oranges. Apples cost $1.50 each and oranges cost $2 each. If she buys a apples and r oranges, which inequality represents her budget?
- 1.50a + 2r < 60
- 1.50a + 2r ≤ 60
- 1.50a + 2r ≥ 60
- 1.50a + 2r = 60
Click to reveal solution →
Maria has at most $60 to spend on apples and oranges. Apples cost $1.50 each and oranges cost $2 each. If she buys a apples and r oranges, which inequality represents her budget?
- 1.50a + 2r < 60
- 1.50a + 2r ≤ 60
- 1.50a + 2r ≥ 60
- 1.50a + 2r = 60
Click to reveal solution →
Answer: (B) 1.50a + 2r ≤ 60
"At most $60" means she can spend up to and including $60. That's ≤ 60, not < 60.
5If 4(x - 2) > 6x - 14, what is the solution?
- x < 3
- x > 3
- x < -3
- x > -3
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If 4(x - 2) > 6x - 14, what is the solution?
- x < 3
- x > 3
- x < -3
- x > -3
Click to reveal solution →
Answer: (A) x < 3
Distribute: 4x - 8 > 6x - 14.
Subtract 4x: -8 > 2x - 14. Add 14: 6 > 2x.
Divide by 2 (positive — don't flip): 3 > x, i.e., x < 3.
6For the inequality y < 2x + 1, is the point (0, 0) a solution?
- Yes
- No
- Only if x ≥ 0
- Only if x < 0
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For the inequality y < 2x + 1, is the point (0, 0) a solution?
- Yes
- No
- Only if x ≥ 0
- Only if x < 0
Click to reveal solution →
Answer: (A) Yes
Plug in: 0 < 2(0) + 1 → 0 < 1. True. So (0, 0) satisfies the inequality.
7A movie streaming service charges a $5 monthly fee plus $2.50 per movie. If a member wants to spend no more than $30 in a month, what is the maximum number of movies they can watch?
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- 9
- 10
- 11
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A movie streaming service charges a $5 monthly fee plus $2.50 per movie. If a member wants to spend no more than $30 in a month, what is the maximum number of movies they can watch?
- 8
- 9
- 10
- 11
Click to reveal solution →
Answer: (C) 10
Let m = movies. Inequality: 5 + 2.50m ≤ 30.
Subtract 5: 2.50m ≤ 25. Divide by 2.50: m ≤ 10.
Maximum integer is m = 10.
8Which point (x, y) is in the solution region of the system y ≥ x + 1 and y < 2x + 3?
- (0, 0)
- (0, 4)
- (2, 4)
- (2, 8)
Click to reveal solution →
Which point (x, y) is in the solution region of the system y ≥ x + 1 and y < 2x + 3?
- (0, 0)
- (0, 4)
- (2, 4)
- (2, 8)
Click to reveal solution →
Answer: (C) (2, 4)
Check (2, 4) in both: 4 ≥ 2 + 1 = 3 ✓ and 4 < 2(2) + 3 = 7 ✓. Both satisfied.
(Other choices fail at least one inequality — verify by plugging in.)
Frequently asked questions
What is a linear inequality?
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When do I flip the inequality sign?
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What's the difference between < and ≤?
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How do I graph a linear inequality in two variables?
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How do I solve a system of inequalities?
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Keep going
Solving linear equations
Same rules, equations only
Systems of equations
When two equations share variables
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